Weighing the Earth: Measuring G
A twisted fibre, a mirror and a beam of light measure the feeblest force in nature.
Lesson at a glanceShow the key points
- A light rod with small spheres (mass m, length l) hangs from a fine fibre; large spheres M placed at distance r pull them sideways.
- Gravitational torque F·l = (GMm/r²)·l is balanced by the fibre's torque kθ, so G = kθr²/(Mml).
- Moving the large spheres to the other side swings the rod through 2θ; the reflected light beam turns through 4θ, magnifying a tiny angle.
- Once G is known, the Earth's mass follows from g = GM/R²: M = gR²/G ≈ 6 × 10²⁴ kg.
G is so small that two people standing a metre apart attract each other with well under a millionth of a newton. Henry Cavendish measured it in 1798 with little more than a stick, a wire and four lead balls.
The torsion balance
Two small balls of mass m are fixed to the ends of a light rod of length l, which hangs horizontally from a very fine quartz fibre. Two large balls of mass M are placed beside the small ones, on opposite sides, all four centres on one horizontal circle. Each small ball feels a sideways pull
where r is the centre-to-centre distance (a uniform sphere acts like a point at its centre). The two pulls are perpendicular to the rod and turn it the same way, giving a torque . As the rod turns, the fibre twists and pushes back with a torque proportional to the twist, kθ. The rod settles where the two balance:
Making a tiny angle visible
θ is far too small to read off a protractor. So a small mirror is fixed to the fibre and a light beam is bounced off it onto a distant scale. A mirror turned through θ turns the reflected beam through 2θ.
To double the effect again, the big balls are moved to the mirror-image position on the other side. The rod swings from +θ to −θ, a total of 2θ, so the beam sweeps through 4θ. If the spot moves a distance d on a scale a distance D away, , and
Every quantity on the right can be measured. (k itself comes from timing the rod’s slow twisting oscillations.)
In a classroom balance, m = 15 g, l = 10 cm, M = 1.5 kg, r = 4.5 cm and k = 1.0 × 10⁻⁸ N·m/rad. Find the deflection θ and the shift of the light spot on a scale 5.0 m away when the big balls are swapped.
Weighing the Earth
Once G is known, the Earth’s mass follows from the acceleration of a falling apple: , so
- 1A torsion balance balances the gravitational torque Fl against the fibre's torque kθ.
- 2; a mirror and light beam magnify θ (4θ when the big balls are swapped).
- 3With G known, kg.
Check yourself
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