Gravitational Potential Energy
Far apart counts as zero, so every bound pair has negative energy.
Lesson at a glanceShow the key points
- Change in PE when separation goes from r₁ to r₂: U(r₂) − U(r₁) = Gm₁m₂(1/r₁ − 1/r₂) (11.2).
- With U = 0 at infinite separation: U(r) = −Gm₁m₂/r (11.3).
- For many particles, add the PE of every pair: N particles have N(N − 1)/2 pairs.
- Bringing particles together from far away, gravity does positive work and U becomes more negative.
- Near the surface, U changes by approximately mgh for a small height h.
Near the ground, lifting something by h costs mgh. But g weakens with distance, so for satellites and rockets we need the exact potential energy of two bodies at any separation.
Moving one particle away from another
Recall from the chapter on energy that for a conservative force, . Hold particle m₁ fixed and move m₂ outward so the separation grows from r to r + dr. Gravity pulls m₂ back toward m₁ with , so it does work , and the potential energy rises by . From r₁ to r₂:
Where to put zero
Only differences matter, so we may choose where U = 0. The natural choice is infinite separation, where the particles no longer interact. Put r₁ → ∞ and r₂ = r:
U depends only on the separation, not on which particle moved, so the formula holds generally. For three or more particles, add the potential energy of every pair: N particles form N(N − 1)/2 pairs.
Four 200 g balls are brought from very far apart to the corners of a square of side 10 cm. Find the gravitational potential energy of the arrangement and the work done by gravity.
Where mgh comes from
For a body of mass m lifted from the surface (r = R) to a height h, the exact formula gives
How much energy is needed just to lift a 1000 kg satellite from the Earth’s surface to a height equal to the Earth’s radius (6400 km)? Compare with mgh.
- 1.
- 2With U = 0 at infinity: , always negative.
- 3Systems: add U over all N(N − 1)/2 pairs.
- 4mgh is the small-height approximation of the exact formula.
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