Junction Transistors
A small current controlling a large one.
Lesson at a glanceShow the key points
- Emitter–base forward-biased, collector–base reverse-biased.
- I_E = I_B + I_C; β = α/(1 − α).
- Voltage gain βR_L/R_BE; power gain β²R_L/R_BE; g_m = ΔI_C/ΔV_BE.
- Oscillator = amplifier + LC feedback.
Sandwich a very thin slice of one type of semiconductor between two of the other type and a tiny current can control a big one. That is a transistor: the amplifier, the oscillator and, billions of times over, the computer chip.
Structure
A junction transistor has three layers. In an n-p-n transistor a thin p-type layer sits between two n-type layers; in a p-n-p it is the other way round.
- Base (middle): very thin (about 1 μm) and lightly doped.
- Emitter: heavily doped; it supplies the charge carriers.
- Collector: moderately doped, and larger, to collect them. The collector–base junction has a larger area than the emitter–base one.
Each layer has a terminal, so the transistor is a three-terminal device. In normal use the emitter–base junction is forward-biased and the collector–base junction is reverse-biased. In the symbol, an arrow on the emitter shows the direction of current through the emitter–base junction: outward for n-p-n (current from base to emitter), inward for p-n-p.
How it works (n-p-n)
The forward bias makes the emitter pour electrons into the base. The base is so thin, and has so few holes, that almost none of the electrons recombine there. Instead they reach the collector–base junction, where the reverse bias’s field sweeps them into the collector. They return to the emitter through the external batteries.
So the collector current IC is nearly the whole emitter current IE. The small difference, from electrons that leave through the base terminal, is the base current IB, typically 1–5 % of IE. Holes play a small part too, but the lightly doped base keeps it minor. By Kirchhoff’s junction rule:
Why a small base current controls the collector current: a few electrons from the emitter recombine with holes in the base, and some holes diffuse into the emitter. If those lost holes were not replaced, the base would charge negatively and choke off the flow from the emitter. The base current replaces them. Increase it a little and the collector current rises a lot.
Three ways to connect it
One terminal is shared between the input and output circuits and kept at zero potential: common-emitter (the most used), common-base or common-collector.
The common-emitter amplifier
A battery biases the base–emitter junction forward; another holds the collector positive. The signal vi is added in series in the base circuit, and the output is taken across a large load resistor RL in the collector circuit.
- The forward-biased base–emitter junction has a small input resistance RBE, so the signal changes the base current by ΔIB = vi/RBE.
- The collector current changes by ΔIC = βΔIB.
- The voltage across the load changes by vo = RLΔIC.
A change of 5.0 mA in emitter current causes a change of 4.9 mA in collector current. What change in base current gives the same 4.9 mA collector change? Find α and β.
In a common-emitter amplifier, adding a 15 mV signal to the base–emitter voltage changes the base current by 10 μA and the collector current by 1.5 mA. The load is 4.0 kΩ. Find β, the input resistance, the transconductance, the voltage gain and the power gain.
The oscillator
An oscillator produces an alternating voltage of chosen frequency using only DC supplies. It combines a common-emitter amplifier with an LC circuit that resonates at
Part of the output is fed back to the input through the LC network. The amplifier boosts it, part is fed back again, and so on: the circuit sustains itself with no external signal. Only the frequency ν₀ that the LC network favours builds up, and changing L or C tunes it.
Characteristics
For an n-p-n transistor in common-emitter mode, the base circuit is the input and the collector circuit the output.
- Input characteristic (IB against VBE): like a forward-biased diode. Almost no current until VBE passes the barrier, then a rapid rise, though IB stays in microamperes because most carriers go on to the collector.
- Output characteristics (IC against VCE, one curve per IB): IC rises steeply at small VCE, then levels off at a value set mainly by IB. Larger base currents give higher curves.
- 1n-p-n or p-n-p: thin, lightly doped base; heavily doped emitter; larger collector.
- 2Normal use: emitter–base forward-biased, collector–base reverse-biased.
- 3I_E = I_B + I_C; α = I_C/I_E ≈ 0.95–0.99; β = I_C/I_B = α/(1 − α) ≈ 20–100+.
- 4Common-emitter amplifier: current gain β, voltage gain βR_L/R_BE, power gain β²R_L/R_BE; g_m = ΔI_C/ΔV_BE.
- 5Oscillator = amplifier + LC feedback at ν₀ = 1/2π√LC.
Check yourself
Keep exploring
Hand-picked videos, simulations and readings that explain this idea from a different angle.