Colours of Thin Films
Why a soap bubble shimmers: light reflected from its two faces interferes.
Lesson at a glanceShow the key points
- A film splits light into many reflected and transmitted waves; neighbouring waves differ in optical path by 2μd at normal incidence.
- Transmitted light: bright when 2μd = nλ (17.9), dim when 2μd = (n + ½)λ (17.10).
- Reflection from an optically denser medium adds a phase change of π (like a string tied to a heavier one); from a rarer medium, none.
- Reflected light: so the conditions swap: dark when 2μd = nλ (17.11), bright when 2μd = (n + ½)λ (17.12). Energy conservation demands it.
- With white light, different thicknesses favour different wavelengths, giving the colours of oil slicks and bubbles.
A drop of oil on a wet road, a soap bubble, the wing of a dragonfly: all shimmer with colours that shift as you tilt your head. None of them contain any dye. The colours come from interference.
Many reflections
Take a thin transparent film of thickness d and refractive index μ, with parallel faces. Light falling on it splits at the top face: part reflects, part enters. The part inside splits again at the bottom face: part leaves, part reflects back up, and so on. The film sends out a whole series of reflected waves and a series of transmitted waves, each weaker than the last. The film can be viewed by either set.
Take nearly normal incidence. Each transmitted wave has made one more round trip inside the film than the one before: an extra geometrical path 2d, through a medium of index μ. So neighbouring waves differ in optical path by
Seen by transmitted light
Seen by reflected light: a twist
You might expect the same conditions for reflected light. But think about energy: if a film both transmitted and reflected a wavelength strongly, where would the extra energy come from? Whatever the film transmits strongly it must reflect weakly, and vice versa. Experiment confirms that the conditions swap:
The reason: a phase flip on reflection
Recall a pulse on a light string running into a heavier one: the reflected pulse is inverted, a phase change of π. Reflected from a lighter string, it isn’t. Light behaves the same way: a medium of higher refractive index is optically denser.
Air → film (rarer to denser): sudden phase change of π, an extra half wavelength.
Film → air (denser to rarer): no sudden phase change.
So even when 2μd is a whole number of wavelengths, the first two reflected waves end up half a cycle apart and cancel.
Where the colours come from
In white light, a given thickness satisfies the bright condition for some wavelengths and the dark condition for others. Those colours are reflected strongly or weakly, and the eye sees the mixture. Where the thickness varies, as in a draining soap film or a spreading oil slick, the colours vary in bands. A film much thinner than a wavelength reflects almost nothing (2μd ≈ 0, so the reflection is dark): the top of a soap film turns black just before it bursts.
What is the smallest thickness of a film of refractive index 1.38 (in air) that strongly reflects 550 nm light?
- 1A thin film gives many reflected and transmitted waves; neighbours differ in optical path by 2μd (normal incidence).
- 2Transmitted light: bright for 2μd = nλ, dim for 2μd = (n + ½)λ.
- 3Reflection from a denser medium adds a phase change of π, so reflected light is dark for 2μd = nλ and bright for 2μd = (n + ½)λ.
- 4In white light, different thicknesses favour different colours.
Check yourself
Keep exploring
Hand-picked videos, simulations and readings that explain this idea from a different angle.