Pressure from Molecules
Add up the momentum delivered by every molecule bouncing off a wall.
Lesson at a glanceShow the key points
- A molecule hitting a wall transfers 2mvₓ and returns every 2L/vₓ: average force mvₓ²/L.
- Isotropy: v̄ₓ² = v̄²/3. So p = ⅓ρv̄² (24.1), pV = ⅓Mv̄² = ⅓Nmv̄² (24.2–24.3).
- rms speed v_rms = √(v̄²) = √(3p/ρ) = √(3pV/M).
- Total translational KE K = ½Mv²_rms = (3/2)pV (24.4).
Count the knocks of molecules on a wall, add up their momentum, and out comes the pressure of a gas.
One molecule, one wall
A gas fills a cubical box of side L. Take one molecule with velocity components vₓ, v_y, v_z. When it strikes the face A₁ perpendicular to x, vₓ reverses and the other components are unchanged (elastic collision). Its momentum changes by −2mvₓ, so the wall receives
It then crosses to the opposite face and back, a distance 2L in x, before hitting A₁ again. So it strikes A₁ every 2L/vₓ seconds, that is vₓ/2L times per second. The average force it exerts on A₁ is
All the molecules
Adding up, F = (m/L)Σvₓ². Since no direction is special, Σvₓ² = Σv_y² = Σv_z² = ⅓Σv². With N molecules, total mass M = mN and density ρ = M/L³, the pressure F/L² is
The rms speed
The square root of the mean square speed is the root-mean-square (rms) speed:
Oxygen at 1 atm (1.0 × 10⁵ Pa) and 0°C has density 1.43 kg/m³. Find the rms speed of its molecules.
Translational kinetic energy
The total translational kinetic energy of the molecules is
A room holds 60 m³ of air at 1.0 × 10⁵ Pa. What is the total translational kinetic energy of its molecules?
- 1A molecule hitting a wall delivers 2mvₓ; it returns every 2L/vₓ.
- 2p = ⅓ρv̄²; pV = ⅓Mv̄² = ⅓Nmv̄².
- 3v_rms = √(3p/ρ).
- 4Translational KE K = ½Mv²_rms = (3/2)pV.
Check yourself
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