Geometrical Optics
Mirrors, prisms and lenses: where light goes when we treat it as rays.
Reflection & Plane Mirrors
Why your reflection seems to stand as far behind the mirror as you stand in front.
Light’s wavelength is tiny compared with mirrors, lenses and the things we look at, so diffraction can usually be ignored and light treated as straight rays. That is geometrical optics, and it starts with the humble mirror.
The laws of reflection
A ray of light striking a smooth surface is reflected so that
- the angle of incidence equals the angle of reflection (both measured from the normal), and
- the incident ray, the reflected ray and the normal all lie in one plane.
The image in a plane mirror
Put a point source S in front of a flat mirror. A ray SA striking the mirror at right angles comes straight back. Another ray SB, striking at angle i, reflects along BC. Extend AS and BC behind the mirror: they meet at a point I. Using the law of reflection, the triangles SAB and IAB are congruent, so SA = AI. Every reflected ray, extended backwards, passes through the same point I.
An eye receiving the reflected rays can’t tell where they really came from; they seem to diverge from I. So I is the image of S. No light actually passes through I, so it is a virtual image.
You stand 3.0 m from a wall mirror and walk 1.0 m toward it. How far are you from your image now, and how much did that distance change?
Curved surfaces
The same laws work for a curved mirror, point by point. At the point where a ray strikes, imagine the plane just touching the surface (the tangent plane) and draw the normal perpendicular to it. The angles of incidence and reflection are measured from that normal.
- 1Angle of incidence = angle of reflection; incident ray, reflected ray and normal are coplanar.
- 2A plane mirror forms a virtual image as far behind it as the object is in front (SA = AI).
- 3On curved mirrors the laws hold at each point, using the normal to the tangent plane.
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Spherical Mirrors & the Sign Convention
The vocabulary of curved mirrors, and a sign rule that makes one formula fit every case.
Look into a shiny spoon: one side shows you upside down, the other right way up but tiny. Curved mirrors can magnify, shrink and flip images, and a few words and one sign rule are enough to describe them all.
The parts of a spherical mirror
A spherical mirror is a piece cut from a hollow sphere, usually glass silvered on one side. If light reflects from the hollow (inner) side it is a concave mirror; from the bulging (outer) side, a convex mirror.
- Centre of curvature C: the centre of the sphere. Its radius is the radius of curvature R.
- Pole P: the middle point of the mirror’s surface.
- Principal axis: the line through P and C.
Focus
Send a narrow beam parallel to the principal axis onto a concave mirror, close to the pole. The reflected rays all cross the axis at (nearly) one point: the focus F. On a convex mirror the reflected rays spread out, but they seem to come from one point behind the mirror, its focus.
The distance PF is the focal length; the plane through F perpendicular to the axis is the focal plane.
Rays far from the axis miss the focus slightly, which matters for big mirrors (you’ll meet this again under aberrations).
Tracing an image
To find the image of a point, follow two rays from it to the mirror. At each point of incidence the normal is the line to C; reflect each ray by the laws of reflection.
- If the reflected rays actually meet, they form a real image (it can be caught on a screen).
- If they diverge, they seem to come from a virtual image.
Real and virtual objects
Usually rays diverge from a point object in front of the mirror: a real object. But a lens could send converging rays toward the mirror; the point where they would have met, behind the mirror, then acts as a virtual object. In short: where the incident rays meet (or would meet) is the object; where the reflected rays meet (or seem to) is the image.
The sign convention
Mirror formulas involve the object distance, image distance, focal length and radius. To make one formula work in every situation we use a coordinate sign convention:
- The pole is the origin and the principal axis is the x-axis.
- The positive x-direction is the direction of the incident light (usually left to right).
- u, v, R and f are the x-coordinates of the object, image, centre of curvature and focus: positive if on the positive side of P, negative otherwise.
- Heights above the axis are positive, below negative.
| Situation (light from the left) | u | v | R, f |
|---|---|---|---|
| Concave mirror, real image | − | − | − |
| Concave mirror, virtual image (object inside F) | − | + | − |
| Convex mirror, real object | − | + | + |
- 1Concave (reflects on the inside) and convex (outside) mirrors; pole P, centre C, radius R, principal axis.
- 2Paraxial rays parallel to the axis meet at (or seem to come from) the focus F; PF is the focal length.
- 3Real image: rays meet. Virtual image: rays only seem to come from it. Converging incident rays define a virtual object.
- 4Coordinate convention: pole at origin, + along incident light, u, v, R, f are x-coordinates; up is positive.
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The Mirror Formula & Magnification
One equation finds every mirror image; another tells you its size and whether it's upside down.
With the sign convention in hand, a single short equation tells you where any spherical mirror forms its image, and a second one tells you how big it is and which way up.
Deriving the mirror formula
A point object O sits on the axis of a concave mirror. One ray goes along the axis, hits the pole P and comes straight back. Another ray OA hits the mirror at A and reflects through I, where the image forms. CA is the normal at A, so it bisects the angle OAI.
Call the angles that OA, CA and IA make with the axis α, β and γ, and let θ be the angle of incidence (= angle of reflection). The exterior angle of a triangle equals the sum of the opposite interior angles:
For a paraxial ray A is close to P, so the small angles are AP/PO, AP/PC and AP/PI:
With light from the left, O, I and C are all on the negative side: PO = −u, PI = −v, PC = −R. Substituting:
Focal length
A very distant object (u → ∞) sends parallel rays, which meet at the focus: v = f. Then 1/f = 2/R:
An object is 10 cm in front of a convex mirror of radius of curvature 30 cm. Where is its image?
Extended objects and magnification
For an object AB standing on the axis, find the image of the tip B with two convenient rays, then drop a perpendicular to the axis:
- a ray parallel to the axis reflects through F (or away from F for a convex mirror);
- a ray aimed at C hits the mirror normally and comes straight back;
- a ray through F reflects parallel to the axis;
- a ray striking the pole reflects symmetrically about the axis.
Comparing the right-angled triangles formed by the ray that strikes the pole gives the lateral magnification:
A 3.0 cm tall object stands at 1.25 f in front of a concave mirror (f is the magnitude of its focal length). Find the image’s height and orientation.
- 11/u + 1/v = 2/R = 1/f for every spherical mirror (with signs); f = R/2.
- 2Parallel → through F; toward C → straight back; through F → parallel; at P → symmetric.
- 3m = h₂/h₁ = −v/u; negative m is inverted.
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Refraction at a Flat Surface
Why a pool looks shallower than it is.
A swimming pool always looks shallower than it really is, and a straw in a glass looks bent at the surface. Both are images made by refraction at a flat surface.
Snell’s law with refractive indices
When a ray crosses from medium 1 into medium 2, the angles obey
The image formed by a flat surface
An object O lies in medium 1 (index μ₁) below a flat surface; medium 2 (index μ₂) is above. A ray OP straight up crosses without bending. A ray OA striking the surface at a small angle i bends to angle r. Traced back, the two rays meet at I, a virtual image of O.
For small angles, sin ≈ tan, so sin i ≈ PA/PO and sin r ≈ PA/PI, and Snell’s law gives
Looking from air (μ₂ = 1) at an object in a medium of index μ:
The object seems raised toward the observer by
A glass block (μ = 1.5) 4.5 cm thick rests on a page. How far raised does the print appear, viewed from above?
The bottom of a pool appears 1.5 m deep when viewed from directly above. How deep is it really? (μ of water = 1.33.)
- 1sin i / sin r = v₁/v₂ = μ₂/μ₁.
- 2A flat surface forms a virtual image of an object below it.
- 3Viewed from air near the normal: μ = real depth / apparent depth.
- 4The image is raised by Δt = (1 − 1/μ)t.
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Total Internal Reflection & Optical Fibres
Past a certain angle, glass becomes a perfect mirror, and that is how fibres carry light.
Look up at the surface of a swimming pool from underwater and, beyond a certain angle, it shines like a silver mirror. Glass and water can reflect perfectly, without any silvering at all.
The critical angle
When light passes from an optically denser medium (larger μ) into a rarer one (smaller μ), it bends away from the normal: the angle of refraction r is bigger than the angle of incidence i.
Increase i and r grows faster. At one angle of incidence, the critical angle θc, the refracted ray skims along the surface (r = 90°). For larger i, no angle r can satisfy Snell’s law: there is no refracted ray at all, and all the light reflects back into the denser medium. This is total internal reflection.
Usually the critical angle is quoted for light going from a medium into air. Putting μ₂ = 1 and r = 90° in Snell’s law:
The critical angle for diamond is 24.4°. Find its refractive index.
What is the critical angle for glass of refractive index 1.5?
Optical fibres
An optical fibre is a very thin thread of glass or plastic, only micrometres across. Light sent into one end strikes the wall at a very glancing angle, far beyond the critical angle, and is totally reflected. It bounces along inside the fibre, even round bends, with almost no loss. A bundle of fibres is a light pipe.
Uses
- Seeing inside the body: a light pipe is passed down into, say, the stomach. Some fibres carry light in; others carry the image back out to the viewer.
- Communication: thousands of telephone signals, mixed into the light, can travel along one fibre at once, far more clearly than in ordinary cables.
- 1From denser to rarer, a ray bends away from the normal; at the critical angle it grazes the surface.
- 2Beyond θc all the light is reflected: total internal reflection.
- 3Into air: sin θc = 1/μ (glass ≈ 42°, water ≈ 49°, diamond ≈ 24°).
- 4Optical fibres trap light by total internal reflection; they are coated with a lower-index layer. Used in medicine and communication.
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The Prism & Minimum Deviation
A prism bends light by an amount that is smallest when the ray passes through symmetrically.
A prism turns a beam of light through an angle, bending it toward its base. How much depends on the angle at which the light goes in, and there’s one special angle that gives the least bending of all.
Following a ray through a prism
A prism’s cross-section is a triangle; two of its faces are the refracting surfaces, meeting at the angle of the prism A. A ray strikes the first face at angle of incidence i and refracts at angle r. Inside, it meets the second face at angle r′ and leaves at angle i′, the angle of emergence, provided r′ is not beyond the critical angle.
Without the prism, the ray would have gone straight on. The angle between that original direction and the final ray is the angle of deviation δ. Each face turns the ray, by (i − r) and (i′ − r′), so
The normals at the two faces meet at some point V. In the four-sided figure formed by the apex, the two points of incidence and V, two angles are right angles, so the angle at V is 180° − A. In the triangle formed by the ray inside and the two normals, r + r′ plus that same angle is 180°. So:
Minimum deviation
As i changes, so does δ, and for one particular i it is smallest. At that point the ray passes through the prism symmetrically: i = i′ (and r = r′).
Why symmetric?
Light paths are reversible. Suppose the minimum happened with i bigger than i′. Send light backwards along the emerging ray: it retraces the path exactly, with the same deviation, which must also be the minimum. But now the angle of incidence is the old i′ and the emergence the old i, so incidence is smaller than emergence, which contradicts the assumption. The same argument rules out i < i′. If the minimum is unique, it must have i = i′.
Refractive index from minimum deviation
At minimum deviation δm: r = A/2 and i = (A + δm)/2. Snell’s law μ = sin i / sin r then gives
Thin prisms
If A is small, δm is small too and the sines can be replaced by the angles:
A 60° prism gives a minimum deviation of 38°. Find its refractive index.
By how much does a thin glass prism of angle 4° (μ = 1.5) deviate a ray?
- 1r + r′ = A and δ = i + i′ − A.
- 2δ is least when the ray passes symmetrically: i = i′, r = r′ = A/2.
- 3μ = sin[(A + δm)/2] / sin(A/2).
- 4Thin prism: δ = (μ − 1)A.
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Refraction at a Curved Surface
The single curved boundary that lenses, eyes and fish bowls are built from.
Before lenses, master one curved boundary. The front of your eye, the side of a goldfish bowl and each face of a lens are all single spherical surfaces between two media.
Setting up
Two transparent media, of refractive indices μ₁ and μ₂, are separated by a spherical surface with centre of curvature C. A point object O in medium 1 lies on the line through C, which meets the surface at P. We use the same sign convention as for mirrors: P is the origin, the axis is OPC, positive in the direction of the incident light; u, v and R are the x-coordinates of object, image and centre.
Deriving the formula
The ray OP hits the surface normally and goes straight on. Another ray OD makes a small angle α with the axis and refracts along DI, where the image I forms. CD is the normal at D. With β the angle DCP and γ the angle DIC, the triangles give
For small angles Snell’s law becomes μ₁i = μ₂r, and α ≈ DP/PO, β = DP/PC, γ ≈ DP/PI. Putting these together:
With PO = −u, PI = +v, PC = +R:
An object in air is 20 cm from a convex glass surface (μ = 1.5) of radius 40 cm. Locate the image.
Extended objects: magnification
A ray from the tip Q of an extended object heading for C meets the surface normally and goes straight on, so the image of Q lies on the line QC. Similar triangles and the formula above give the lateral magnification:
A small 2.0 cm fish is 30 cm from the near side of a spherical bowl of water (μ = 1.33), seen by someone outside. The bowl’s surface has radius 15 cm. Ignore the thin glass. Where does the fish appear, and how big?
- 1μ₂/v − μ₁/u = (μ₂ − μ₁)/R, using the coordinate sign convention.
- 2A ray aimed at the centre of curvature passes undeviated.
- 3Lateral magnification m = μ₁v/(μ₂u).
- 4R → ∞ recovers refraction at a flat surface.
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Thin Lenses & the Lens Maker's Formula
Two curved surfaces close together: how their curvatures set a lens's focal length.
A lens is just two spherical surfaces close together. Put the last lesson’s formula to work twice and out comes the rule every lens designer uses.
Thin lenses
A lens is a piece of transparent material bounded by two spherical surfaces (or one spherical and one flat). It is thin if its thickness is small compared with the object and image distances. Its two surfaces have centres C₁ and C₂ and radii R₁ and R₂. The line through C₁ and C₂ is the principal axis, and the point P of the lens on it is the optical centre.
The foci
A narrow beam parallel to the axis, near the optical centre, is refracted twice and emerges either converging to a point F₂ or diverging as if from F₂. The lens is then a converging (convex) or diverging (concave) lens.
If the medium is the same on both sides, the two focal lengths are equal. “Focus” and “focal length” will mean F₂ and PF₂.
Sign convention
As before: optical centre at the origin, principal axis as the x-axis, positive along the incident light; u, v, f, R₁, R₂ are x-coordinates; heights up are positive. With light from the left, f is positive for a converging lens and negative for a diverging lens.
| Lens (light from the left) | R₁ | R₂ | f |
|---|---|---|---|
| Biconvex | + | − | + |
| Biconcave | − | + | − |
| Plano-convex, curved face first | + | ∞ | + |
| Converging meniscus (both centres to the right) | + (smaller) | + | + |
The lens maker’s formula
Let the lens (index μ₂) sit in a medium of index μ₁. At the first surface, light goes from μ₁ into μ₂ and forms an image at v₁. Since the lens is thin, take the origin at P for both surfaces:
That image is the object for the second surface, where light goes from μ₂ back into μ₁:
Adding the two eliminates v₁:
For u → ∞, v = f. In air (μ₁ = 1, μ₂ = μ):
Combining the two equations gives the lens formula:
A biconvex lens has both radii 30 cm and refractive index 1.6. Find its focal length.
- 1Thin lens: two spherical surfaces; principal axis through C₁C₂; optical centre P.
- 2Parallel rays converge to (or seem to diverge from) F₂; f > 0 for converging, f < 0 for diverging lenses.
- 3Lens maker's formula in air: 1/f = (μ − 1)(1/R₁ − 1/R₂).
- 4Lens formula: 1/v − 1/u = 1/f.
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Images by Lenses & Magnification
Three easy rays and one ratio describe every image a single lens can make.
A camera, a projector and a magnifying glass can all use the same convex lens. Only the object’s distance changes, and with it the size, position and orientation of the image.
Three easy rays
To find the image of the tip of an object, trace any two of these rays:
- Through the optical centre: straight on. Near its centre a thin lens is like a thin slab with parallel faces, so the ray is neither turned nor noticeably shifted.
- Parallel to the axis: emerges through F₂ (convex), or as if from F₂ (concave).
- Through F₁ (or heading for it, for a concave lens): emerges parallel to the axis.
Where the emerging rays cross (or seem to cross, traced back) is the image of the tip; drop a perpendicular to the axis for the whole image.
Magnification
The ray through the optical centre makes similar triangles of object and image, with PO = −u and PO′ = +v:
A 3.0 cm object is 15 cm from a convex lens of focal length 20 cm. Find the image.
An object is 15 cm from a convex lens of focal length 10 cm. Where is the image and what is the magnification?
A summary
| Convex lens, object at | Image |
|---|---|
| Very far (∞) | At F₂: real, inverted, tiny |
| Beyond 2F₁ | Between F₂ and 2F₂: real, inverted, smaller (camera, eye) |
| At 2F₁ | At 2F₂: real, inverted, same size |
| Between F₁ and 2F₁ | Beyond 2F₂: real, inverted, larger (projector) |
| At F₁ | At infinity |
| Inside F₁ | Same side: virtual, erect, larger (magnifying glass) |
A concave lens always gives a virtual, erect, smaller image of a real object, lying between the lens and F.
- 1Ray through the optical centre: straight on. Parallel ray: through (or from) F₂. Ray through F₁: emerges parallel.
- 2m = v/u for lenses; negative m means inverted.
- 3Convex lens: real inverted images for objects beyond F, virtual magnified erect image inside F.
- 4Concave lens: always virtual, erect, diminished (for real objects).
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Power & Lens Combinations
Add powers for lenses in contact; account for the gap when they're apart.
Opticians don’t talk about focal lengths: a prescription says “+2.5” or “−1.75”. That number is the lens’s power, and powers of lenses in contact simply add.
Power of a lens
A lens of focal length +25 cm has power 1/0.25 m = +4 D; one of −50 cm has power −2 D. A short focal length means a strong lens.
Two thin lenses in contact
Lens L₁ forms an image of the object at v₁; this image is the object for L₂, which forms the final image at v. Since the lenses touch and are thin, the same distance v₁ applies to both:
So the pair behaves exactly like one equivalent lens:
A convex lens of focal length 25 cm is placed in contact with a concave lens of focal length 40 cm. Find the power and focal length of the combination.
How much a lens bends a ray
A ray from an axial object O strikes a thin lens at height h and crosses the axis again at the image I. Its direction changes by δ = α + β, where α ≈ h/PO and β ≈ h/PI for small angles. With PO = −u, PI = v:
Two lenses a distance apart
Separated lenses are not equivalent to one thin lens in general. But for a parallel incident beam they are. A ray at height h₁ is turned by δ₁ = h₁/f₁ at the first lens, travels distance d, reaches the second lens at height h₂ = h₁ − dδ₁, and is turned by δ₂ = h₂/f₂. An equivalent lens of focal length F would turn it by δ = h₁/F = δ₁ + δ₂. Substituting:
The equivalent lens sits where the incident ray and the final emergent ray, extended, cross: a distance dF/f₁ from the second lens, on the side the light comes from (18.23).
Two convex lenses of focal length 20 cm are 10 cm apart. A parallel beam enters. Find the equivalent focal length and where the equivalent lens is.
- 1Power P = 1/f in dioptres (f in m); converging +, diverging −.
- 2Thin lenses in contact: 1/F = 1/f₁ + 1/f₂, P = P₁ + P₂.
- 3A thin lens turns a ray at height h by δ = h/f.
- 4Separated by d (parallel beam): 1/F = 1/f₁ + 1/f₂ − d/f₁f₂; equivalent lens dF/f₁ before the second lens.
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Defects of Images (Aberrations)
Real mirrors and lenses blur, smear and colour their images; designers fight back.
Our neat formulas assumed thin lenses, small apertures and rays close to the axis. Real instruments break these rules, and their images show it as blur, smears, coloured fringes and bent lines. These defects are called aberrations.
Happen even with light of a single colour: spherical aberration, coma, astigmatism, curvature, distortion.
Happen because the refractive index, and so the focal length, depends on the colour of the light.
Spherical aberration
A spherical mirror or lens brings only paraxial rays to a single focus. Rays striking further out, the marginal rays, focus at a slightly different point (for a concave mirror, closer to it). The image of a point becomes a blurred patch.
The rays crowd along a bright curve, the caustic (you can see one inside a coffee cup in sunlight). On a screen the image is a disc; moving the screen finds where the disc is smallest, the circle of least confusion. The distance between the paraxial and marginal foci measures the aberration.
Reducing it
- Parabolic mirrors focus all parallel rays at one point, and a lamp at the focus sends out a parallel beam: car headlights use them.
- Stops: an opaque sheet with a small hole lets only a narrow pencil of rays through. Sharper, but dimmer.
- Share the bending between both lens surfaces. A plano-convex lens imaging a distant object does much better with its curved side toward the object than its flat side.
- Combine convex and concave lenses, whose spherical aberrations are opposite, so they partly cancel.
For a single lens forming a real image of a real object, spherical aberration can be reduced but never removed completely.
Coma
For a point object off the axis, rays through different rings of the lens form circles of different sizes whose centres are shifted. Together they make a comet-shaped smear: coma. Careful choice of radii and stops reduces it.
Astigmatism
For an off-axis point, the image is also spread along the axis. Move a screen and you first get a short line image, then a different shape, staying in rough focus over a range. (This lens defect shares its name with, but is not the same as, the eye defect.)
Curvature of field
The best image of a flat object is often formed not on a flat plane but on a curved surface. It is closely linked to astigmatism; both are reduced by stops in the right places.
Distortion
If the magnification changes with distance from the axis, an extended object is imaged out of shape: straight lines come out curved.
Chromatic aberration
The refractive index of glass varies with wavelength, so a lens has a slightly different focal length for each colour: longest for red, shortest for violet. In white light each colour forms its own image.
- Axial (longitudinal) chromatic aberration: the separation along the axis between the images for the extreme colours. A convex lens puts violet nearer than red (positive); a concave lens does the opposite (negative).
- Lateral chromatic aberration: since m depends on v, the images for different colours differ in size.
- 1Aberrations: monochromatic (spherical, coma, astigmatism, curvature, distortion) and chromatic.
- 2Spherical aberration: marginal and paraxial rays focus differently; caustic, circle of least confusion. Remedies: parabolic mirrors, stops, sharing bending, combinations.
- 3Coma: comet-shaped images of off-axis points. Astigmatism: spread along the axis. Curvature: best image on a curved surface. Distortion: straight lines imaged curved.
- 4Chromatic: f largest for red, smallest for violet; axial and lateral; cured for two colours by an achromatic combination.